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Home/ Questions/Q 896277
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T14:42:06+00:00 2026-05-15T14:42:06+00:00

Consider the following PowerShell script: function Alpha { # write-output ‘Uncomment this line and

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Consider the following PowerShell script:

function Alpha {
# write-output 'Uncomment this line and see what happens.';
return 65;
}

function Bravo {
$x = Alpha;
$y = $x -eq 65;
return $y;
}

$z = Bravo;
echo $z;

On my computer (which is running Windows XP SP3, .NET 4.0, and PowerShell 2.0 RTM), when the script is run, the script’s output is as expected (True). However, when “the line” is uncommented (and the script is run again), instead of seeing the same output prepended by Uncomment this line..., I am only seeing 65. Can someone please explain what is going on? Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T14:42:07+00:00Added an answer on May 15, 2026 at 2:42 pm

    Write-Output just writes an object to the pipeline. If you need a message displayed on the screen, use Write-Host.

    So, to take apart what happens here, that was kind of a preliminary. If you uncomment the line, both the string 'Uncomment this line and see what happens.' and the number 65 are outputs of the function, so when calling Bravo the variable $y no longer holds just a single value but instead the array 'Uncomment this line and see what happens.',65.

    Now the comparison operators work differently if the left operand is an array instead of a scalar value. If the left operand is an array they simply return all elements from the array where the condition would be $true. In this case, since you compare with 65, it will return all items that are equal to 65. So the result is no longer a boolean but instead an array of objects (or in this case, just a single object) – 65.

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