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Home/ Questions/Q 178889
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Asked: May 11, 20262026-05-11T14:18:37+00:00 2026-05-11T14:18:37+00:00

Consider the following snippet: struct ObjectInterface { virtual ~ObjectInterface() {} virtual void Print(std::ostream& target)

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Consider the following snippet:

struct ObjectInterface {     virtual ~ObjectInterface() {}     virtual void Print(std::ostream& target) const = 0; };  struct Foo : ObjectInterface {     virtual void Print(std::ostream& target) const     {         target << 'Foo';     } };  struct Bar : ObjectInterface {     virtual void Print(std::ostream& target) const     {         target << 'Bar';     } }; 

Is there any way to change Print in ObjectInterface to the standard ‘std::ostream& operator<<‘-type of output? I can’t make it work.

EDIT: I’m basically trying to figure out if I can make friend work with virtual.

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  1. 2026-05-11T14:18:38+00:00Added an answer on May 11, 2026 at 2:18 pm

    You need a free function:

    ostream & operator << ( ostream & os, const ObjectInterface & oi ) {     oi.Print( os );     return os; } 
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