Question

Consider the following snippet:

var regex = /^\d+$/; // equivalent to new RegExp('^\\d+$');

console.println(regex.test('000'));  
console.println(regex.test('abc0')); 
console.println(regex.test('ddd')); 

One would expect the output to be:

true
false
false

However, when I run it on Adobe Acrobat X, which runs JavaScript 1.8, it outputs:

false
false
true

What’s going on here?

Answer 1

It’s likely a result of string processing on the way to the Javascript interpreter, causing your \d to be interpreted as d. An extra backslash (apparently) does the trick.

/^\\d+$/