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Home/ Questions/Q 958285
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T00:50:24+00:00 2026-05-16T00:50:24+00:00

Consider the following source code. I have two classes CBar and CFoo. CFoo inherits

  • 0

Consider the following source code. I have two classes CBar and CFoo. CFoo inherits from CBar. The output of this source code is

Bar 
Foo 
Bar 

I was expecting

Bar 
Foo 
Foo

Where did I go wrong?
What I was thinking was that since the CFoo object has a Speak function that overrides the CBar speak function. When I call The Speak() function from a CBar function on an object that is CFoo the CFoo Speak function would be executed. But that assumption appears to be wrong.

class CBar
{
    public:
        void Speak() { 
            printf(" Bar \n"); 
        }

        void DoStuff() {
            this->Speak(); 
        }
};


class Cfoo : public CBar 
{
    public:
        void Speak() { 
            printf(" Foo \n"); 
        }

        void DoStuff() {
            CBar::DoStuff(); 
        }
};



int _tmain(int argc, _TCHAR* argv[])
{
    CBar b;
    b.Speak(); 

    Cfoo f;
    f.Speak();

    f.DoStuff(); 
    return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T00:50:25+00:00Added an answer on May 16, 2026 at 12:50 am

    In C++, you need to use virtual to enable polymorphism. Otherwise, all Speak() is doing in CFoo is hiding Speak() in CBar.

    class CBar 
    { 
        public: 
            virtual void Speak() {  // Note virtual keyword
                printf(" Bar \n");  
            } 
    
            void DoStuff() { 
                this->Speak();  
            } 
    }; 
    
    
    class Cfoo : public CBar  
    { 
        public: 
            void Speak() {  // Overrides the virtual method Speak()
                printf(" Foo \n");  
            } 
    
            void DoStuff() { // Hides CBar::DoStuff() method
                CBar::DoStuff(); 
            } 
    }; 
    
    
    
    int _tmain(int argc, _TCHAR* argv[]) 
    { 
        CBar b; 
        b.Speak();  
    
        // Speak() is a virtual function, so calling Speak() on a CFoo or
        // a CBar pointer will call the most derived implementation of Speak(). 
        Cfoo f; 
        f.Speak(); 
    
        /* My example */
        // Since CFoo "is-a" CBar, this conversion is safe.
        CBar* bar = &f;
        // Since Speak() is a virtual function, this will call CFoo's implementation
        // of Speak(), not CBar's.
        bar->Speak();
        /* End example */
    
        // Because CBar::DoStuff() is hidden, this calls CFoo::DoStuff() instead.
        f.DoStuff();
        return 0; 
    } 
    
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