Question

Consider the following table:

create table temp (                       name int,     a int,     b int )  insert into temp (name, a, b) values (1, 2, 3)  insert into temp (name, a, b) values (1, 4, 5)  insert into temp (name, a, b) values (2, 6, 7) 

I want to select *(all fields) with distinct [name]. In the case of two or more rows having the same [name], to choose whether to display the first (1, 2, 3) or the second row(1, 4, 5) the rule can be to choose the one with greater [b].

Can you point how must I write this stored procedure?

Answer 1

Here is one way to do this sql 2000 and up version

select t1.* from( select name,max(B) as MaxB from temp group by name) t2  join temp t1 on t1.a = t2.MaxB and t1.name = t2.name 

SQL 2005 and up version

select name, a, b from ( select m.*, row_number() over ( partition by name order by B desc) as rn from temp m ) m2 where m2.rn = 1;