Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 100591
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T00:36:31+00:00 2026-05-11T00:36:31+00:00

Consider the following table: mysql> select * from phone_numbers; +————-+——+———–+ | number | type

  • 0

Consider the following table:

mysql> select * from phone_numbers; +-------------+------+-----------+ | number      | type | person_id | +-------------+------+-----------+ | 17182225465 | home |         1 | | 19172225465 | cell |         1 | | 12129876543 | home |         2 | | 13049876543 | cell |         2 | | 15064223454 | home |         3 | | 15064223454 | cell |         3 | | 18724356798 | home |         4 | | 19174335465 | cell |         5 | +-------------+------+-----------+ 

I’m trying to find those people who have home phones but not cells.

This query works:

mysql> select h.*     -> from phone_numbers h     -> left join phone_numbers c     -> on h.person_id = c.person_id     -> and c.type = 'cell'     -> where h.type = 'home'     -> and c.number is null; +-------------+------+-----------+ | number      | type | person_id | +-------------+------+-----------+ | 18724356798 | home |         4 | +-------------+------+-----------+ 

but this one doesn’t:

mysql> select h.*     -> from phone_numbers h     -> left join phone_numbers c     -> on h.person_id = c.person_id     -> and h.type = 'home'     -> and c.type = 'cell'     -> where c.number is null; +-------------+------+-----------+ | number      | type | person_id | +-------------+------+-----------+ | 19172225465 | cell |         1 | | 13049876543 | cell |         2 | | 15064223454 | cell |         3 | | 18724356798 | home |         4 | | 19174335465 | cell |         5 | +-------------+------+-----------+ 

The only difference between the two is the location of the h.type = 'home' condition – in the first it’s in the where clause and in the second it’s part of the on clause.

Why doesn’t the second query return the same result as the first?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-11T00:36:32+00:00Added an answer on May 11, 2026 at 12:36 am

    In the second SQL, the condition h.type = ‘home’ is part of the outer join conditions, and is not a filter on the results. For all records where h.type=’cell’, the condition h.type = ‘home’ is FALSE and so no ‘matching’ c row is found – so c.number is null, which is your only filtering (WHERE) condition.

    In pseudo-code your 2nd SQL works like this:

    for each row in phone_numbers h /* Note this is ALL home AND cell phones */    select c.number from phone_numbers c    where h.person_id = c.person_id    and h.type = 'home'    and c.type = 'cell';    if c.number is null (i.e. no row found)      display h.*    end if end loop; 
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 112k
  • Answers 112k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer If you wanted to achieve your goal and avoid the… May 11, 2026 at 9:59 pm
  • Editorial Team
    Editorial Team added an answer I had this exact same problem and never solved it.… May 11, 2026 at 9:59 pm
  • Editorial Team
    Editorial Team added an answer I finally figured this out! On SO of all places,… May 11, 2026 at 9:59 pm

Related Questions

Consider the following table: mysql> select * from phone_numbers; +-------------+------+-----------+ | number | type
Consider the following 2 tables: Table A: id event_time Table B id start_time end_time
I've got a query like this: update table set status = 1 where status
I am using MSSQL 2005 Server and I have the following SQL query. IF
I'm trying to select a column from a single table (no joins) and I

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.