Question

Consider these two traits:

trait Poked extends Actor {
  override def receive = {
    case Poke(port, x) => ReceivePoke(port, x)
  }

  def ReceivePoke(port: String, x: Any)
}

trait Peeked extends Actor {
  override def receive = {
    case Peek(port) => ReceivePeek(port)
  }

  def ReceivePeek(port: String)
}

Now consider I can create a new Actor that implements both traits:

val peekedpoked = actorRef(new Actor extends Poked with Peeked)

How do I compose the receive handlers? i.e., the receiver should be something like the following code, though “automatically generated” (i.e., all traits should compose):

def receive = (Poked.receive: Receive) orElse (Peeked.receive: Receive) orElse ...

Answer 1

You can use super[T] to reference members of particular super classes/traits.

For example:

trait IntActor extends Actor {
    def receive = {
        case i: Int => println("Int!")
    }
}

trait StringActor extends Actor {
    def receive = {
        case s: String => println("String!")
    }
}

class IntOrString extends Actor with IntActor with StringActor {
    override def receive = super[IntActor].receive orElse super[StringActor].receive
}

val a = actorOf[IntOrString].start
a ! 5 //prints Int!
a ! "Hello" //prints String!

Edit:

In response to Hugo’s comment, here’s a solution that allows you to compose the mixins without having to manually wire their receives together. Essentially it involves a base trait with a mutable List[Receive], and each mixed-in trait calls a method to add its own receive to the list.

trait ComposableActor extends Actor {
  private var receives: List[Receive] = List()
  protected def registerReceive(receive: Receive) {
    receives = receive :: receives
  }

  def receive = receives reduce {_ orElse _}
}

trait IntActor extends ComposableActor {
  registerReceive {
    case i: Int => println("Int!")
  }
}

trait StringActor extends ComposableActor {
  registerReceive {
    case s: String => println("String!")
  }
}

val a = actorOf(new ComposableActor with IntActor with StringActor).start
a ! 5 //prints Int!
a ! "test" //prints String!

The only thing to keep in mind is that the order of the receives should not be important, since you won’t be able to easily predict which one is first in the chain, though you could solve that by using a mutable hashmap instead of a list.