Consider this case:
public Class1 {
public static final String ONE = "ABC";
public static final String TWO = "DEF";
}
public Class2 {
public void someMethod() {
System.out.println(Class1.ONE + Class1.TWO);
}
}
Typically you would expect the compiler to inline the ONE and TWO constants. However, is this behavior guaranteed? Can you deploy at runtime Class2 without Class1 in the classpath, and expect it to work regardless of compilers, or is this an optional compiler optimization?
EDIT: Why on earth do this? Well I have a constant that would be shared between two ends of an application (client and server over RMI) and it would be very convenient in this particular case to put the constant on a class that can only be on one side of that divide (as it is logically the one that owns that constant value) rather than have it in an arbitrary constants class just because it needs to be shared by both sides of the code. At compile time its all one set of source files, but at build time it is divided by package.
It’s guaranteed to be treated as a constant expression, and guaranteed to be interned by section 15.28 of the JLS:
…
Now, that doesn’t quite say it’s guaranteed to be inlined. However, section 13.1 of the spec says:
In other words, even if the expression itself weren’t a constant, there should be no reference to
Class1. So yes, you’re okay. That doesn’t necessarily guarantee that the concatenated value is used in the bytecode, but the bits referenced earlier guarantee that the concatenated value is interned, so I’d be hugely surprised if it didn’t just inline the concatenated value. Even if it doesn’t, you’re guaranteed that it’ll work withoutClass1.