Question

Consider this code:

byte b=1;
long l=1000;
b += l;

I would expect the last statement to require an explicit cast because,
b+=l is evaluated as b = b+l and
(b+l) part gives an integer.
Integer cannot be assigned to byte without an explicit cast?

Answer 1

Well to start with, b+l gives a long, not an int…

… but compound assignment operators have other behaviour. As per JLS section 15.26.2:

A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T) ((E1) op (E2)), where T is the type of E1, except that E1 is evaluated only once.

Note the cast to T.