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Home/ Questions/Q 285501
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:33:08+00:00 2026-05-12T05:33:08+00:00

Consider this code: class Jm44 { public static void main(String args[]){ int []arr =

  • 0

Consider this code:

class Jm44 {

public static void main(String args[]){

      int []arr = {1,2,3,4};
      for ( int i : arr )
      {
         arr[i] = 0;
       }

      for ( int i : arr )
      {
         System.out.println(i);
      }


     }

}

It prints:

0 
0 
3 
0

What’s this? For-each is supposed to run over all the elements in the array, why would it run arr[3]=0 but not arr[2]=0?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:33:08+00:00Added an answer on May 12, 2026 at 5:33 am

    If you look at what happens to arr in the first loop, it becomes obvious.

        int[] arr = {1, 2, 3, 4};
        for (int i : arr) {
            System.out.println("i = " + i);
            arr[i] = 0;
            System.out.println("arr = " + Arrays.toString(arr));
        }
    
        for (int i : arr) {
            System.out.println(i);
        }
    

    This prints:

    i = 1
    arr = [1, 0, 3, 4]
    i = 0
    arr = [0, 0, 3, 4]
    i = 3
    arr = [0, 0, 3, 0]
    i = 0
    arr = [0, 0, 3, 0]
    0
    0
    3
    0
    

    You are modifying the values in the array, using the values in the array as indexes. The “foreach” loop goes through the values of the array, not the indexes of the array. After removing the syntactic sugar, here is what your foreach loop actually is:

        int[] arr = {1, 2, 3, 4};
        for (int index = 0; index < arr.length; index++) {
            int i = arr[index];
            arr[i] = 0;
        }
    
        for (int i : arr) {
            System.out.println(i);
        }
    

    To be able to index the array, you need to use the traditional for loop, like this:

        int[] arr = {1, 2, 3, 4};
        for (int i = 0; i < arr.length; i++) {
            arr[i] = 0;
        }
    
        for (int i : arr) {
            System.out.println(i);
        }
    
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