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Home/ Questions/Q 4102142
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T20:47:16+00:00 2026-05-20T20:47:16+00:00

Consider this code example: var source = null; $.ajax({ […], success:function(data) { source =

  • 0

Consider this code example:

var source = null;

$.ajax({
    [...],
    success:function(data)
    {
        source = data;
        alert(source);
    }
});

alert(source);

Now: inside of the success handler, everything is fine, I get the correct data from the webservice and everything is just great. But as soon as JS leaves the $.ajax and is done with it the variable source is null again.

Tell me why. It must be some JavaScript specfic stuff I’m not familiar with. :/

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  1. Editorial Team
    Editorial Team
    2026-05-20T20:47:16+00:00Added an answer on May 20, 2026 at 8:47 pm

    It is probably because you are forgetting AJAX is asynchronous. The source variable will be undefined until the success callback is completed.

    Doing alert(source) beneath that code (outside of the $.ajax()) is almost guaranteed to be undefined.

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