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Home/ Questions/Q 7658885
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T13:15:37+00:00 2026-05-31T13:15:37+00:00

Consider this code: function Foo() { } Foo.prototype.alert = function() { alert(this); } (new

  • 0

Consider this code:

function Foo() {
}

Foo.prototype.alert = function() {
    alert(this);
}

(new Foo()).alert();

When executed (in jsfiddle), the alert shows that ‘this’ is the window object. Changing the last line to :

var foo = new Foo();
foo.alert();

works as expected.

Why is the difference?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T13:15:37+00:00Added an answer on May 31, 2026 at 1:15 pm

    It seems that you are missing a semi-colon:

    function Foo() {
    }
    
    Foo.prototype.alert = function() {
        alert(this);
    }; //Semi-colon here!
    
    (new Foo()).alert();​
    

    Here’s a fiddle in which it appears to work as you expect.

    What is actually happening is that the alert method gets called immediately, with a new instance of Foo passed into it, and alert is then called on the return value (which is undefined):

    Foo.prototype.alert = function() {
        alert(this);
    }(new Foo()).alert();
    

    As @Nemoy has mentioned, if you just use new Foo().alert() you will get the expected behaviour because automatic semi-colon insertion will put a semi-colon in the right place for you (the lack of a semi-colon doesn’t change the meaning of the code). And as the new operator has the highest precedence, the parentheses are not required.

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