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Home/ Questions/Q 365721
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T13:33:51+00:00 2026-05-12T13:33:51+00:00

Consider this code: LARGE_INTEGER l; size_t s; if (s < l.QuadPart) return 1; return

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Consider this code:

LARGE_INTEGER l;
size_t s;
if (s < l.QuadPart) return 1;
return 0;

When this is compiled under x64 it generates the C4018 signed/unsigned mismatch compiler warning (Ignore the uninitialized local variable warning).

The warning is fine, since QuadPart is LONGLONG which is signed and size_t is unsigned.

But when I compile this under 32-bit there is no warning? How come? Under 32-bit LONGLONG is still signed and size_t is unsigned.

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  1. Editorial Team
    Editorial Team
    2026-05-12T13:33:52+00:00Added an answer on May 12, 2026 at 1:33 pm

    On 32-bit LONGLONG is equivalent to signed __int64 and size_t is equivalent to unsigned int. unsigned int has range that completely fits into signed __int64 range, so the compiler widens (does integer promotion) size_t to signed __int64 before the comparison and there’s no warning.

    On 64-bit LONGLONG is again equivalent to signed __int64 but size_t is equivalent to unsigned __int64, so now size_t no longer fits into LONGLONG and the compiler can’t perform any kind of promotion automatically, hence the warning.

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