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Home/ Questions/Q 7934749
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T21:43:35+00:00 2026-06-03T21:43:35+00:00

Consider this example of two similar C++ member functions in a class C: void

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Consider this example of two similar C++ member functions in a class C:

void C::function(Foo new_f) {
    f = new_f;
}

and

void C::function(Foo new_f) {
    this->f = new_f;
}

Are these functions compiled in the same manner? Are there any performance penalties for using this-> (more memory accesses or whatever)?

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  1. Editorial Team
    Editorial Team
    2026-06-03T21:43:36+00:00Added an answer on June 3, 2026 at 9:43 pm

    Yes, it’s exactly the same and you’ll get the same performance.

    The only time you really must use the this-> syntax is when you have an argument to the function with the same name as an instance variable you want to access. Using the name of the variable by itself will refer to the argument so you need the this->. Of course, you could just rename the argument too. And, as ildjarn has pointed out in the comments also, you need to use this in certain situations to call functions that are dependent because this is implicitly dependent (you can read more about that though).

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