Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6629419
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T22:15:27+00:00 2026-05-25T22:15:27+00:00

Consider this example which prints out some device type stats. (DeviceType is an enum

  • 0

Consider this example which prints out some device type stats. (“DeviceType” is an enum with a dozenish values.)

Multiset<DeviceType> histogram = getDeviceStats();
for (DeviceType type : histogram.elementSet()) {
    System.out.println(type + ": " + histogram.count(type));
}

What’s the simplest, most elegant way to print the distinct elements in the order of their frequency (most common type first)?

With a quick look at the Multiset interface, there’s no ready-made method for this, and none of Guava’s Multiset implementations (HashMultiset, TreeMultiset, etc) seem to automatically keep elements frequency-ordered either.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T22:15:28+00:00Added an answer on May 25, 2026 at 10:15 pm

    I just added this feature to Guava, see here for the Javadoc.

    Edit: usage example of Multisets.copyHighestCountFirst() as per the original question:

    Multiset<DeviceType> histogram = getDeviceStats();
    for (DeviceType type : Multisets.copyHighestCountFirst(histogram).elementSet()) {
        System.out.println(type + ": " + histogram.count(type));
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Consider this simple example (which displays in red): echo -e \033[31mHello World\033[0m It displays
Consider this example table (assuming SQL Server 2005): create table product_bill_of_materials ( parent_product_id int
Consider this example (typical in OOP books): I have an Animal class, where each
Consider this example: zh_Hant_HK format = yy'年'M'月'd'日' ah:mm Not sure if you can see
Consider this example: #include <iostream> class myclass { public: void print() { std::cout <<
Please consider this example class: [Serializable] public class SomeClass { private DateTime _SomeDateTime; public
Consider this contrived example: # Dispatch on value of fruit_kind: TYPE_A = :apple TYPE_B
Consider this classic example used to explain what not to do with forward declarations:
Consider this problem: I have a program which should fetch (let's say) 100 records
Consider this example: public class Factory { private List<ISubFactory> subFactories; public Factory(List<ISubFactory> subFactories) {

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.