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Home/ Questions/Q 6689351
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:30:33+00:00 2026-05-26T05:30:33+00:00

Consider this little program: #include <stdio.h> int main() { char c = 0xFF; printf(%d\n,

  • 0

Consider this little program:

#include <stdio.h>
int main()
{
    char c = 0xFF;
    printf("%d\n", c);

    return 0;
}

Its output is -1, as expected (considering char is signed in my
system). What I’m trying to do is to make it print 255. This is of
course a simplification of the real situation, where I can’t just define
c as unsigned.

The first possible change would be using %u as formatter instead, but
the usual type promotion rules apply here, and the number is printed as
232 – 1.

So is there any way to read the signed char as unsigned before it gets
promoted to an int? I could create a pointer to a unsigned char set to the
address of c, and dereference it later, but not sure if this is the best
approach.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:30:34+00:00Added an answer on May 26, 2026 at 5:30 am

    c is being promoted using signed promotion rules. Cast c to unsigned to use unsigned promotion.

    printf("%u\n", (unsigned char)c);
    

    Unsigned char will be promoted to unsigned int.

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