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Home/ Questions/Q 6000893
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T00:45:33+00:00 2026-05-23T00:45:33+00:00

Consider this query: SELECT s.*, COUNT( ssh_logs.id ) AS ssh_count FROM servers s LEFT

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Consider this query:

SELECT s.*, COUNT( ssh_logs.id ) AS ssh_count FROM servers s 
LEFT JOIN logs ssh_logs ON s.ip_address = ssh_logs.server_ip

I am under the impression the LEFT JOIN shows all rows on the left table, regardless of whether there’s a match for the ON condition.

SELECT s.* FROM servers s

Returns 12 entries, while the first query returns only 1 where the ip addresses match.

So how do I get the first query to display all the rows in servers table alongwith the joined table data?

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  1. Editorial Team
    Editorial Team
    2026-05-23T00:45:33+00:00Added an answer on May 23, 2026 at 12:45 am

    The aggregate function count() collapses all rows into one.
    Do a group by to see the count per ip-address.

    SELECT s.*, COUNT(ssh_logs.id) AS ssh_count FROM servers s  
    LEFT JOIN logs ssh_logs ON s.ip_address = ssh_logs.server_ip 
    GROUP BY s.ip_address
    

    This will work best if servers.ip_address is an unique field for servers (primary key or unique index).
    If servers has duplicate ip_addresses than this query will group those ip_addresses together and hide data that should be hidden.

    However given the fact that these are servers it is logical to assume ip_address is unique.

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