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Home/ Questions/Q 560907
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:23:37+00:00 2026-05-13T12:23:37+00:00

Consider this regex: <(.*)> Applied against this string: <2356> <my pal ned> <!@%@> Obviously,

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Consider this regex: <(.*)>

Applied against this string:

<2356> <my pal ned> <!@%@>

Obviously, it will match the entire string because of the greedy *. The best solution would be to use a non-greedy quantifier, like *?. However, many languages and editors don’t support these.

For simple cases like the above, I’ve gotten around this limitation with a regex like this: <([^>]*)>

But what could be done with a regex like this? start (.*) end

Applied against this string:

start 2356 end start my pal ned end start !@%@ end

Is there any recourse at all?

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:23:38+00:00Added an answer on May 13, 2026 at 12:23 pm

    If the end condition is the presence of a single character you can use a negative character class instead:

    <([^>]*)>
    

    For more complexes cases where the end condition is multiple characters you could try a negative lookahead, but if lazy matching is not supported the chances are that lookaheads won’t be either:

    ((?!end).)*
    

    Your last recourse is to construct something horrible like this:

    (en[^d]|e[^n]|[^e])*
    
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