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Home/ Questions/Q 8152511
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T15:44:08+00:00 2026-06-06T15:44:08+00:00

Consider this simple example – public class Person { private String name; private Date

  • 0

Consider this simple example –

public class Person
 {
    private String name;
    private Date dateOfBirth;

    // getters and setters here...
 }

In order to initialize Person as a Spring bean, I can write the following.

<bean id = "Michael" class = "com.sampleDomainName.Person">
<property name = "name" value = "Michael" />
</bean>

But in the above bean definition, how can I set the dateOfBirth?

For eg. I want to set the dateOfBirth as

1998-05-07
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T15:44:09+00:00Added an answer on June 6, 2026 at 3:44 pm

    One of the answers mentioned here is useful, but it needs additional information. The constructor arguments for the CustomDateEditor need to be supplied.

    <bean class="org.springframework.beans.factory.config.CustomEditorConfigurer">
      <property name="customEditors">
        <map>
          <entry key="java.util.Date"> <ref local = "customDateEditor" /> 
          </entry> 
        </map>
      </property> 
    </bean>
    
    <bean id = "customDateEditor" class="org.springframework.beans.propertyeditors.CustomDateEditor">
        <constructor-arg>
          <bean class="java.text.SimpleDateFormat">
              <constructor-arg value="yyyy-MM-dd" />
           </bean>
        </constructor-arg>
        <constructor-arg value="true" /> 
    </bean>
    

    Now we can do

    <property name="dateOfBirth" value="1998-05-07" />
    
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