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Home/ Questions/Q 1077767
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:37:28+00:00 2026-05-16T21:37:28+00:00

Consider this try / except block I use for checking error message stored in

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Consider this try/except block I use for checking error message stored in e.

Try/Catch to get the e

queryString = "SELECT * FROM benchmark WHERE NOC = 2"
try:
    res = db.query(queryString) 
except SQLiteError, e:
    # `e` has the error info 
    print `e`

The e object here contains nothing more than the above string. When python reports an unhandled error, however, it shows a pretty detailed info as below:

Traceback (most recent call last):
  File "fool.py", line 1, in 
    open("abc.zyz", "r")
IOError: [Errno 2] No such file or directory: 'abc.zyz'

My question is, how can I get the information such as above (the file and the line number etc.)? Or, if e contains this info, how is it stored inside it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:37:29+00:00Added an answer on May 16, 2026 at 9:37 pm

    This will show the trace to the error.

    import traceback
    
    try:
        res = db.query(queryString) 
    except SQLiteError, e:
        # `e` has the error info 
        print `e`
        for tb in traceback.format_tb(sys.exc_info()[2]):
            print tb
    
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