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Home/ Questions/Q 650889
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T22:06:07+00:00 2026-05-13T22:06:07+00:00

Consider: #!/usr/bin/perl use strict; use warnings; my %hash; foreach (1 .. 10) { $hash{$_}

  • 0

Consider:

#!/usr/bin/perl
use strict;
use warnings;

my %hash;
foreach (1 .. 10) {
    $hash{$_} = $_;
}
foreach(sort(keys %hash)) {
    print $_ . ":  " . "$hash{$_}" . "\n";
}

When I execute the above code, the result is as below:

1:  1
10:  10
2:  2
3:  3
4:  4
5:  5
6:  6
7:  7
8:  8
9:  9

I expect "10: 10" to be the last one that is printed. Why does Perl give me a surprise in this case?

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  1. Editorial Team
    Editorial Team
    2026-05-13T22:06:08+00:00Added an answer on May 13, 2026 at 10:06 pm

    sort always defaults to string comparison.

    If you want a numeric sort, you have to be explicit.

    sort {$a <=> $b} (keys %hash)
    
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