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Home/ Questions/Q 7929823
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T20:12:54+00:00 2026-06-03T20:12:54+00:00

consider you are searching for Cs that are appeared after a Bs. Why following

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consider you are searching for Cs that are appeared after a Bs.
Why following code returns -1 instead of 2:

console.log('abc'.search(/(?=b)c/));
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  1. Editorial Team
    Editorial Team
    2026-06-03T20:12:57+00:00Added an answer on June 3, 2026 at 8:12 pm

    Because (?= is for lookahead, not lookbehind.

    q(?=u) matches a q that is followed by a u, without making the u part of the match.


    And before you ask: JavaScript regex does not support lookbehind. In this simple case, however, you can use a workaround based on lookahead:

    var index = 'abc'.search(/b(?=c)/);
    if (index !== -1) index++;
    console.log(index);
    

    This works because you’re looking for the position of c preceded by b, but this is logically the same as one greater than the position of b followed by c.

    Before you get too excited, however: you do not need regex for this. At all.

    var index = 'abc'.indexOf('bc');
    if (index !== -1) index++;
    console.log(index);
    
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