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Home/ Questions/Q 7432585
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T09:28:52+00:00 2026-05-29T09:28:52+00:00

Considering that this prints something like [E] [F] [A] [C] [A] [B] [F] [B]

  • 0

Considering that this prints something like

[E] [F] [A] [C] [A] 
[B] [F] [B] [B] [D] 
[C] [C] [C] [C] [C]

The following wait 5 seconds and print a row instead of executing each [...] and wait 1 second, why?

    for (int i = 0; i <= 2; i++) {
        for (int j = 0; j <= 4; j++) {
            int a = randomInt(0, 5);
            sleep(1);
            cout << "[" << allowed[a] << "] ";
            usciti[i][j] = allowed[a];
        }
        cout << endl;
    }
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  1. Editorial Team
    Editorial Team
    2026-05-29T09:28:53+00:00Added an answer on May 29, 2026 at 9:28 am

    It’s probably because you are not flushing the std::cout stream until the endl (which flushes as well). You could use a call to cout.flush() to do that.

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