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Home/ Questions/Q 5939653
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:51:30+00:00 2026-05-22T15:51:30+00:00

Considering the following table: create table inttest ( someint INT(10) NULL DEFAULT NULL );

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Considering the following table:

create table inttest (
    someint INT(10) NULL DEFAULT NULL
);

When I insert some random values

insert into inttest 
  (someint) 
values 
  (1),(2),(3),(1),(2),(NULL);

and execute the query

select *
  from inttest 
 where someint != 1;

MySQL returns 2,3,2 but not the NULL value. Is this correct? Should I extend my query with OR someint IS NULL or is it a bug in my MySQL installation?

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:51:31+00:00Added an answer on May 22, 2026 at 3:51 pm
    SELECT 1 != NULL;
    -- Output: NULL
    

    Comparison operators return TRUE, FALSE or NULL.

    You’re expecting NULL != 1 to give you TRUE but, sensibly, you get NULL for the comparison you make. This is because comparing anything with NULL is meaningless: NULL is not a value!.

    Here’s a cunning trick whereby you could get the NULL in the resultset if you still really want it. The trick relies on reversing the logic, then manually excluding the NULL possibility:

    SELECT * FROM `inttest`
     WHERE IF(`someint` = 1, FALSE, TRUE);
    

    A more obvious approach might be:

    SELECT * FROM `inttest`
     WHERE `someint` != '1'
        OR `someint` IS NULL;
    
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