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Home/ Questions/Q 6386545
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Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T03:02:23+00:00 2026-05-25T03:02:23+00:00

Console debug shows me that array is ex. [2], but I need [2]. Why

  • 0

Console debug shows me that array is ex. [“2”], but I need [2].

Why casting doesnt’work?

function filterElements(deals) {

    var result = deals,
        categories= $('#deals-categories').data('current_category');
        if (categories != undefined && categories.length > 0) {
            for (var i; i < categories.length; i++) {
                categories[i] = parseInt(categories[i]);
            }
            console.log(categories, 'cats');
                result = $.grep(result, function(e) {
                    return $.inArray(e.category_id, categories) != -1;
     });                
        }
    return result;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T03:02:24+00:00Added an answer on May 25, 2026 at 3:02 am

    You need to initialize var i = 0 in the loop declaration.

    Full code cleanup:

    function filterElements(deals) {
    
        var result = deals,
            categories = $('#deals-categories').data('current_category');
    
            if (categories && categories.length) {
                for (var i=0; i<categories.length; i++) {
                    categories[i] = parseInt(categories[i], 10);
                }
                console.log(categories, 'cats');
                result = $.grep(result, function(e) {
                    return $.inArray(e.category_id, categories) !== -1;
                });                
            }
    
        return result;
    }
    
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