Question

const char* test(bool i)
{
    const char t[] = "aa\n";
    const char* p = "bbb\n";
    if(i)
        return p;
    return t;
}
int main(array<System::String ^> ^args)
{
     printf(test(true));
     printf(test(false));
     return 0;
}

That returns something of sort:

 bbb
 %^&$^$%

It is clear that test(false) returns a pointer to a local variable. The question is that p is also local variable. Why the memory for “bbb\n” is not cleaned after the function returns. I thought const char[] is interpreted same way as const char* but it is not true as it seems.

Answer 1

p is a local variable, which you return by value, but points to a string literal, which resides in read-only memory, not in the automatic memory allocated for the method.

Returning t and the using it indeed results in undefined behavior.

Also, don’t think of pointers and arrays to be equivalent.