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Home/ Questions/Q 8955403
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T14:32:50+00:00 2026-06-15T14:32:50+00:00

content = ‘abcdd’ import re,os,sys def test(): print content list = re.findall(r'[.\n]+’,content) print list

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content = 'abcdd'


import re,os,sys
def test():
    print content
    list = re.findall(r'[.\n]+',content)
    print list

if __name__ == '__main__':
    test()

I know ‘.’ represent any charaters except ‘\n’

so [.\n] should represent any characters

but the result is []

why

can you help me ?

thank you in avdanvce !

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  1. Editorial Team
    Editorial Team
    2026-06-15T14:32:51+00:00Added an answer on June 15, 2026 at 2:32 pm

    . inside character class [] loses its special meaning of “all characters (except newline or not depending on flag)” and is only a plain full stop ..

    So [.\n] only matches full stop . or new line character.

    If you want to match any character (without exception), one trick is to form a character class of complementing character classes, e.g. [\s\S]. This is useful when the regular expression of the language doesn’t support DOTALL option, which makes . matches any character.

    However, since Python supports DOTALL option (re.DOTALL), so you can make use of it.

    Note that for Python, . excludes only \n. For other languages, it may excludes more: Javascript.

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