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Home/ Questions/Q 8615575
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T05:24:43+00:00 2026-06-12T05:24:43+00:00

Context I have 3 buttons on several lines (edit, delete, unsuscribe). This 3 buttons

  • 0

Context

I have 3 buttons on several lines (edit, delete, unsuscribe).

This 3 buttons are 3 different classes but the same click handler.

This classes are equals to the names of 3 actions using for an ajax call.

So into the click handler, I need to retrieve the specific part of the selector which has been clicked.

Currently I use the following code that I wrote

Question

In 2-3 lines and using class=action system, is there a better way to solve my issue?

I’m looking for something like that but I didn’t find:

$.post(url + '&action=' + classClickedIntoTheSelector.replace(/\./g, '') ...

Code + JSFiddle

<button class="actionLink edit btn">Éditer</button>
<button class="actionLink delete btn btn-warning">Supprimer</button>​
$('.edit, .delete').click(function () {
    var a = $('.this, .that').selector.replace(/\./g, '').split(', ');
    var b = $(this).attr('class').split(' ');
    var action;
    
    for (var i = 0; i < a.length; i++) {
        for (var j = 0; j < b.length; j++) {
            action = a[i] == b[j] ? a[i] : action;
        }            
    }
    
    $.post(url + '&action=' + action...
});​
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T05:24:44+00:00Added an answer on June 12, 2026 at 5:24 am

    Finally I used the generic class and a data-attribute:

    <button class="actionLink btn" data-action="edit">Éditer</button>
    <button class="actionLink btn" data-action="delete">Supprimer</button>​
    
    $j('.actionLink').click(function () {
        $.post(url + '&action=' + $(this).data('action'));
    });
    
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