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Home/ Questions/Q 8506431
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T02:35:19+00:00 2026-06-11T02:35:19+00:00

Continue from this: Timed loop, 10 second between Which gave me a great answer

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Continue from this:
Timed loop, 10 second between

Which gave me a great answer on how I could make the loop on the outer for() each 10 seconds. (the Y)

Now I wish to make the inner loop, the X, so loop once each 1 second, and keep the outer loop (the ‘Y’) at 10000ms (10 seconds)

How can I do this?

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  1. Editorial Team
    Editorial Team
    2026-06-11T02:35:20+00:00Added an answer on June 11, 2026 at 2:35 am

    You need to add currentX in a similar way to currentY. Then, instead of incrementing currentY you should increment currentX. If currentX is not less than xnumHigh then set it back to xnumLow and increment currentY.

    Basically you’re just doing the exact same thing as you did to put y on a timer, just with x instead.

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