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Home/ Questions/Q 6985481
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:41:09+00:00 2026-05-27T18:41:09+00:00

Could someone demystify this code which is part of the zentasks example in the

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Could someone demystify this code which is part of the zentasks example in the Play20 framework. I’m curious how this works, granted I’m new to Scala from Java so a lot of things are tough to wrap my head around.

def IsAuthenticated(f: => String => Request[AnyContent] => Result) = 
  Security.Authenticated(username, onUnauthorized) { user =>
    Action(request => f(user)(request))
  }
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  1. Editorial Team
    Editorial Team
    2026-05-27T18:41:10+00:00Added an answer on May 27, 2026 at 6:41 pm

    You need to split up the signature a bit. f is a function that takes a not-yet-computed string => String and returns another function that accepts a Request[AnyContent] and returns a result.

    The Security.Authenticated call accepts two parameters lists. One that has username and onUnauthorized. The second takes a function accepting the user and returning an action.

    The Action.apply method accepts a function Request[AnyContent] => Result

    so, the f is called in ‘curried’ fashion. That is the first function is called, and then the resulting function is immediately used f(user)(request).

    Here’s the same thing desugared (at least, as best I can) and ugly:

    def isAuthenticated(f: => String => Request[AnyContent] => Result) =
      Security.Authenticated(username, onUnauthorized) { user: String =>
         Action.apply { request: Request[AnyContent] =>
           val hiddenTmp: Request[AnyContent] => Result = f(user)
           hiddenTemp.apply(request)
         }
      }
    

    You can see the compiler is doing a bit of work removing type annotations. Hopefully that helps explain how it desugars into raw scala. Essentially, the function does a lot of functional composition.

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