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Could someone explain me what the following snippet of assembly code does?
I’m not really sure what the last line really does.
.def main = r16
.equ O = 5
.equ P = 6
ldi main, 0
ldi r16, (1<<O) | (1<<P)
Im particularly wondering what the last line really does.
Does it load register 16 with the value of a two logical shifs to the left after an OR statement?
Thanks alot.
(1<<O) | (1<<P)is an expression evaluated by the assembler, the result of which (in this case,96) is then substituted in the final machine code.