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Home/ Questions/Q 7504305
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T21:31:52+00:00 2026-05-29T21:31:52+00:00

Could someone explain this to me? var diagramImage = new Kinetic.Shape(function () { var

  • 0

Could someone explain this to me?

var diagramImage = new Kinetic.Shape(function () {
    var context = this.getContext();
    context.beginPath();
    context.lineWidth = 1;
    //This is crazy tricks. It's part of the KineticJS demo website, but how am I able to assign diagramImage.color here?
    context.strokeStyle = diagramImage.color;

    var lastVertice = polygon.Vertices[polygon.Vertices.length - 1];

    context.moveTo(lastVertice.X, lastVertice.Y);

    for (var i = 0; i < polygon.Vertices.length; i++) {
        var vertice = polygon.Vertices[i];
        context.lineTo(vertice.X, vertice.Y);
    }

    context.stroke();
    context.closePath();
});

It seems to me that diagramImage does not exist until the Kinetic constructor returns, but I am able (and seem to need to) assign context’s strokeStyle to diagramImage‘s color — before diagramImage has been created? Why does this work?

EDIT: Full code:

function DrawPolygon(diagramLayer, polygon) {
    var diagramImage = new Kinetic.Shape(function () {
        var context = this.getContext();
        context.beginPath();
        context.lineWidth = 2;
        //This is crazy tricks. It's part of the KineticJS demo website, but how am I able to assign diagramImage.color here?
        context.strokeStyle = diagramImage.color;

        var lastVertice = polygon.Vertices[polygon.Vertices.length - 1];

        context.moveTo(lastVertice.X, lastVertice.Y);

        for (var i = 0; i < polygon.Vertices.length; i++) {
            var vertice = polygon.Vertices[i];
            context.lineTo(vertice.X, vertice.Y);
        }

        context.stroke();
        context.closePath();
    });

    diagramImage.color = "red";

    diagramImage.on("mouseover", function () {
        this.color = "green";
        diagramLayer.draw();
    });

    diagramImage.on("mouseout", function () {
        this.color = "red";
        diagramLayer.draw();
    });

    diagramLayer.add(diagramImage);
    planViewStage.add(diagramLayer);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T21:31:57+00:00Added an answer on May 29, 2026 at 9:31 pm

    Because where you are calling diagramImage.color is within a closure / function that is passed in to the Kinetic.Shape constructor. This function is not called / is not executed by the constructor until after the new instance created by the constructor is assigned to diagramImage.

    Here’s a minimal example that may better explain what’s happening:

    var MyObject = function(f){
      this.myFunc = f; // f is executed sometime later...
    };
    MyObject.prototype.execute = function(){
      this.myFunc();
    };
    
    var myObjInst = new MyObject(function(){
      console.log("myObjInst:", myObjInst);
    });
    myObjInst.execute();
    

    As Twisol noted, this can be improved by using this instead. For example:

    (function(){
      var MyObject = function(f){
        this.myFunc = f; // f is executed sometime later...
      };
      MyObject.prototype.execute = function(){
        this.myFunc();
      };
    
      var myObjInst = new MyObject(function(){
        console.log("myObjInst:", this);
      });
      myObjInst.execute();
    })();
    

    However, as Chris noted, unless documented by the API – there is no guarantee that this will refer to Kinetic.Shape during the callback – so continuing to use diagramImage here may still be the better of these 2 options.

    In short, I think this is not the best API / example / use of JavaScript – and I would not consider this a nuance of JavaScript that you should have to deal with. Sure, these nuances are there if you need them – but you don’t have to.

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