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Home/ Questions/Q 8050899
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T07:11:06+00:00 2026-06-05T07:11:06+00:00

Could someone explain why this line of code isn’t working. No errors are given.

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Could someone explain why this line of code isn’t working. No errors are given. It simply doesn’t resize the image.

image = ImageIO.read(file);

image.getScaledInstance(ImageDisplayBox.getWidth(), ImageDisplayBox.getHeight());
ImageDisplayBox.setIcon(new ImageIcon(image));

I’ve looked at the other answers on Stackoverflow and noticed a lot of people using the .getScaledInstance method.

I (think) it might be the fact that I have it as .setIcon – Although I’m not the best with Java.

The image is printed but displays only the top left of the image due to size.

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  1. Editorial Team
    Editorial Team
    2026-06-05T07:11:08+00:00Added an answer on June 5, 2026 at 7:11 am

    You’re ignoring the returned value. You want:

    image = image.getScaledInstance(ImageDisplayBox.getWidth(),
                                    ImageDisplayBox.getHeight(), 5);
    

    Or maybe to make things clearer:

    Image scaled = image.getScaledInstance(ImageDisplayBox.getWidth(),
                                           ImageDisplayBox.getHeight(), 5);
    ImageDisplayBox.setIcon(new ImageIcon(scaled));
    

    From the docs:

    Creates a scaled version of this image. A new Image object is returned which will render the image at the specified width and height by default. The new Image object may be loaded asynchronously even if the original source image has already been loaded completely.

    Note that that doesn’t say anything about changing the existing image. It just creates a new image with the given size.

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