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Asked: 2026-06-07T19:43:35+00:00

Could someone help me to check my code, no matter what value i clicked,the

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Could someone help me to check my code, no matter what value i clicked,the radio always checked on the last one. it doesn’t postback correctly, however the return “echo” value is right.

Thanks a lot

here is my code 

<html>
  <form id="form" name="form"  method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">

<input type="radio" name="foo" value="Apple" checked="checked" <?php if(isset($_POST['foo']) == 'Apple'): echo "checked='checked'"; endif; ?>/>Apple
<input type="radio" name="foo" value="Banana"  <?php if(isset($_POST['foo']) == 'Banana'): echo "checked='checked'"; endif; ?>/>Banana
<input type="radio" name="foo" value="Orange" <?php if(isset($_POST['foo']) == 'Orange'): echo "checked='checked'"; endif; ?>/>Orange

<input type="submit" value="Confirm" /> </form>

<? if(isset($_POST['foo']))
{echo $_POST['foo'];
}
?>

 </html>
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1 Answer

  1. Editorial Team

    Your comparisons are based on the return value of isset(), when they should be testing the value of $_POST['foo'], like this:

    if(isset($_POST['foo']) && $_POST['foo'] == 'Orange'):

    Otherwise, true == 'Orange' actually comes out true because PHP is loosely typed and doing type coercion behind the scenes, which is why you’re getting this strange result.

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