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Home/ Questions/Q 6146083
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T18:53:37+00:00 2026-05-23T18:53:37+00:00

Could someone please explain why this happening: class Apple { String type; setType(){ System.out.println(inside

  • 0

Could someone please explain why this happening:

class Apple {

   String type;

   setType(){
      System.out.println("inside apple class");
      this.type = "apple";
   }

}

class RedApple extends Apple {

    String type;

    setType() {
      System.out.println("inside red-apple class");
       this.type = "redapple";
    }
}

int main {

    RedApple red = new RedApple();
    Apple apple = (Apple) red;
    apple.setType();

}

But the output produced is:

"inside red-apple class”

Why does the .setType() method execute the sub-class method, and not the super-class method, even though I am up-casting, as can be seen?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T18:53:38+00:00Added an answer on May 23, 2026 at 6:53 pm

    That’s because that’s how polymorphism works in Java: it always uses the most-derived version of the method, which overrides other versions. The only way to get the base-class version is to use super.setType within the most-derived override.

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