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Home/ Questions/Q 6237599
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T11:03:39+00:00 2026-05-24T11:03:39+00:00

Could someone please take a look at this ? You’ll see the first alert

  • 0

Could someone please take a look at this?

You’ll see the first alert prints -1 whereas I was expecting 1. Anyone know why?

Basic code from the fiddle:

<input type="checkbox" value="0" />0
<input type="checkbox" value="1" />1
<input type="checkbox" value="2" />2
<input type="checkbox" value="3" />3
alert($(':checkbox').index("input[value='1']"));
alert($(':checkbox').index("input[value='0']"));
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  1. Editorial Team
    Editorial Team
    2026-05-24T11:03:39+00:00Added an answer on May 24, 2026 at 11:03 am

    You have the selectors reversed:

    Example: http://jsfiddle.net/RaV35/

     // element---v    collection----------v
    alert($("input[value='0']").index(":checkbox"));
    alert($("input[value='1']").index(":checkbox"));
    

    When passing the index()[docs] method a selector, the individual element for which you want the index is the element against which .index() is invoked.

    The selector you pass to .index() represents the collection against which the element in the original jQuery object is tested.

    When the original jQuery object (on the left) also contains a collection, only the first one is tested for its index against the selector on the right. That’s why the one with value="0" was working.

     //   v--- only the first is tested (and it has value="0")...
    $(':checkbox').index("input[value='0']")
     //   ----------------------^ ...and it is at index 0 of this "collection"
    
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