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Home/ Questions/Q 3427130
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T06:47:57+00:00 2026-05-18T06:47:57+00:00

Could someone tell me how I would do this. I have 3 strings. $route

  • 0

Could someone tell me how I would do this. I have 3 strings.

$route = '/user/$1/profile/$2';
$path = '/user/profile/$1/$2';
$url = '/user/jason/profile/friends';

What I need to do is check to see if the url conforms to the route. I am trying to do this as follows.

$route_segments = explode('/', $route);
$url_segments = explode('/', $url);

$count = count($url_segments);
for($i=0; $i < $count; $i++) {
  if ($route_segments[$i] != $url_segments[$i] && ! preg_match('/\$[0-9]/', $route_segments[$i])) {
    return false;
  }
}

I assume the regex works, it’s the first I have ever written by myself. 😀

This is where I am stuck. How do I compare the following strings:

$route = '/user/$1/profile/$2';
$url = '/user/jason/profile/friends';

So I end up with:

array (
    '$1' => 'jason',
    '$2' => 'friends'
);

I assume that with this array I could then str_replace these values into the $path variable?

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  1. Editorial Team
    Editorial Team
    2026-05-18T06:47:57+00:00Added an answer on May 18, 2026 at 6:47 am
    $route_segments = explode('/',$route);
    $url_segments = explode('/',$url);
    $combined_segments = array_combine($route_segments,$url_segments);
    

    Untested and not sure how it reacts with unequal array lengths, but that’s probably what you’re looking for regarding an element-to-element match. Then you can pretty much iterate the array and look for $ and use the other value to replace it.

    EDIT

    /^\x24[0-9]+$/
    

    Close on the RegEx except you need to “Escape” the $ in a regex because this is a flag for end of string (thus the \x24). The [0-9]+ is a match for 1+ number(s). The ^ means match to the beginning of the string, and, as explained, the $ means match to the end. This will insure it’s always a dollar sign then a number.

    (actually, netcoder has a nice solution)

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