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Home/ Questions/Q 9013489
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T03:16:52+00:00 2026-06-16T03:16:52+00:00

Could you please explain why following code does compile and works fine (checked on

  • 0

Could you please explain why following code does compile and works fine (checked on gcc-4.3.4). I thought selective inheritance cannot weaken or even strengthen access to members/methods. Doesn’t it break encapsulation rules?

#include <iostream>

class A {
protected:
    void foo() { std::cout << "foo" << std::endl;  }
};

class B : private A {
public:
    using A::foo;   //foo() becomes public?!
};

int main() {
    B b;
    b.foo();
    return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-06-16T03:16:55+00:00Added an answer on June 16, 2026 at 3:16 am

    From the language point of view, there’s nothing wrong with this (whether it’s good design is another matter).

    Any class can choose to expose to a wider audience things that it has access to.

    In principle, your example is no different to:

    class B : private A {
    public:
        void bar() { foo(); }
    };
    

    except that here foo() is exposed by proxy.

    What you can’t do is the opposite: a publicly derived class can’t restrict access to things that are accessible via the base class.

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