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Home/ Questions/Q 4000642
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T07:48:24+00:00 2026-05-20T07:48:24+00:00

cout << typeid(int&).name(); This, in my opinion, should return int& as a type, not

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cout << typeid(int&).name();  

This, in my opinion, should return int& as a type, not an int, but on GCC 4.5.1 and on VS2010 SP1 beta it returns int. Why is this?

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  1. Editorial Team
    Editorial Team
    2026-05-20T07:48:25+00:00Added an answer on May 20, 2026 at 7:48 am

    This is how typeid is supposed to work. When you apply typeid to a type-id of a reference type, the type_info object refers to the referenced type.

    ISO/IEC 14882:2003, 5.2.8 / 4 [expr.typeid]:

    When typeid is applied to a type-id, the result refers to a type_info object representing the type of the type-id. If the type of the type-id is a reference type, the result of the typeid expression refers to a type_info object representing the referenced type. If the type of the type-id is a class type or a reference to a class type, the class shall be completely-defined. Types shall not be defined in the type-id.

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