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Home/ Questions/Q 533605
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:31:32+00:00 2026-05-13T09:31:32+00:00

CREATE TABLE accounts ( account_name VARCHAR(100) NOT NULL PRIMARY KEY ); CREATE TABLE products

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CREATE TABLE accounts (
 account_name      VARCHAR(100) NOT NULL PRIMARY KEY
);

CREATE TABLE products (
 product_id        INTEGER NOT NULL PRIMARY KEY,
 product_name      VARCHAR(100)
);

CREATE TABLE bugs (
  bug_id            INTEGER NOT NULL PRIMARY KEY,
  bug_description   VARCHAR(100),
  bug_status        VARCHAR(20),
  reported_by       VARCHAR(100) REFERENCES accounts(account_name),
  assigned_to       VARCHAR(100) REFERENCES accounts(account_name),
  verified_by       VARCHAR(100) REFERENCES accounts(account_name)
 );

CREATE TABLE bugs_products (
  bug_id            INTEGER NOT NULL REFERENCES bugs,
  product_id        INTEGER NOT NULL REFERENCES products,
  PRIMARY KEY       (bug_id, product_id)
);

if i execute ‘describe bugs_products’ i get:

 Field      | Type    | Null | Key | Default | Extra |
+------------+---------+------+-----+---------+-------+
| bug_id     | int(11) | NO   | PRI | NULL    |       | 
| product_id | int(11) | NO   | PRI | NULL    |       | 
+------------+---------+------+-----+---------+-------+

how can i also get references information?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:31:33+00:00Added an answer on May 13, 2026 at 9:31 am

    On testing, the foreign keys are not created on my machine using this syntax:

    CREATE TABLE bugs (
      ...
      reported_by       VARCHAR(100) REFERENCES accounts(account_name),
      ...
     ) ENGINE = INNODB;
    

    But they are when I use this create statement:

    CREATE TABLE bugs (
      ...
      reported_by       VARCHAR(100),
      ...
      FOREIGN KEY (reported_by) REFERENCES accounts(account_name)
     ) ENGINE = INNODB;
    

    An easy way to see if foreign keys exist on a table is:

    show create table bugs_products
    

    Or you can query the information schema:

    select
      table_schema
    , table_name
    , column_name
    , referenced_table_schema
    , referenced_table_name
    , referenced_column_name
    from information_schema.KEY_COLUMN_USAGE
    where table_name = 'bugs'
    

    Also check you’re using the InnoDB storage engine. The MyISAM engine does not support foreign keys. You can find the engine like:

    select table_schema, table_name, engine
    from information_schema.TABLES
    where table_name = 'bugs'
    

    If you try to create a foreign key on a MyISAM table, it will silently discard the references and pretend to succeed.

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