Question

     CREATE TABLE `job` (
    `jobId` int(11) NOT NULL auto_increment,
    `jobcode` varchar(25) default NULL,
    `jobname` varchar(255) default NULL,
    `location` varchar(255) default NULL,
    `budget` int(10) unsigned default NULL,
    `year_type` varchar(100) default NULL,
    `worklineId` int(11) default NULL,
     PRIMARY KEY  (`jobId`),
     KEY `NewIndex` (`worklineId`),
     FOREIGN KEY (`worklineId`) REFERENCES `workline` (`worklineId`)
     ) TYPE=InnoDB;

     CREATE TABLE `subjob` (
    `subjobId` int(11) NOT NULL auto_increment,
    `subjobcode` varchar(25) default NULL,
    `subjobname` varchar(255) default NULL,
    `subjobbudget` int(11) unsigned default NULL,
    `jobgoal_date` date default '0000-00-00',
    `jobId` int(11) default NULL,
     PRIMARY KEY  (`subjobId`),
     KEY `NewIndex` (`jobId`),
     FOREIGN KEY (`jobId`) REFERENCES `job` (`jobId`)
     ) TYPE=InnoDB;

     CREATE TABLE `contract` (
    `contractId` int(11) NOT NULL auto_increment,
    `contractcode` varchar(25) default NULL,
    `price` int(11) unsigned default NULL,
    `contractprice` int(11) unsigned default NULL,
    `company` varchar(50) default NULL,
    `signdate` date default '0000-00-00',
    `begindate` date default '0000-00-00',
    `enddateplan` date default '0000-00-00',
    `note` text,
     PRIMARY KEY  (`contractId`)
     ) TYPE=InnoDB;


     CREATE TABLE `subjob_contract` (
    `subjobcontractId` int(11) NOT NULL auto_increment,
    `status` varchar(11) default NULL,
    `contractId` int(11) default NULL,
    `subjobId` int(11) default NULL,
     PRIMARY KEY  (`subjobcontractId`),
     KEY `NewIndex` (`contractId`),
     KEY `NewIndex2` (`subjobId`),
     FOREIGN KEY (`contractId`) REFERENCES `contract` (`contractId`)
     ) TYPE=InnoDB

I m using mysql front 3.2 to manage database,I can add first fk but when i add second fk i got an error following this :
sql execution error #1005. response from the database: can’t create table’.jobstatus#sql-32c_12f2f.frm’ (errno:150). i already define the new index for fk subjobId reference to subjob table what could be the possibility of this error? thank you

Answer 1

Check the datatype and size of the subjobId column on primary table and referenced table. both must be same than it will allow you to create foreign key.