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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T13:01:20+00:00 2026-05-15T13:01:20+00:00

Current scenario, I launch a process that forks, and after a while it aborts().

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Current scenario, I launch a process that forks, and after a while it aborts().
The thing is that both the fork and the original process print to the shell, but after the original one dies, the shell “returns” to the prompt.
I’d like to avoid the shell returning to the prompt and keep as if the process didn’t die, having the child handle the situation there.

I’m trying to figure out how to do it but nothing yet, my first guess goes somewhere around tty handling, but not sure how that works.

I forgot to mention, the shell takeover for the child could be done on fork-time, if that makes it easier, via fd replication or some redirection.

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  1. Editorial Team
    Editorial Team
    2026-05-15T13:01:20+00:00Added an answer on May 15, 2026 at 1:01 pm

    I think you’ll probably have to go with a third process that handles user interaction, communicating with the “parent” and “child” through pipes.

    You can even make it a fairly lightweight wrapper, just passing data back and forth to the parent and terminal until the parent dies, and then switching to passing to/from the child.

    To add a little further, as well, I think the fundamental problem you’re going to run into is that the execution of a command by the shell just doesn’t work that way. The shell is doing the equivalent of calling system() — it’s going to wait for the process it just spawned to die, and once it does, it’s going to present the user with a prompt again. It’s not really a tty issue, it’s how the shell works.

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