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Asked: 2026-06-18T07:39:07+00:00

Current summary of the problem: I am pulling in information from table ‘main’ that

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Current summary of the problem: I am pulling in information from table ‘main’ that lists out Goal Number and Goal Name for a specific ID (there can be up to 10 rows). These are displayed in a table on the web page. I added checkboxes in the first column that reflect the amount of rows in the table. The code for this is below, this part is working correctly. The out put is 3 columns, Checkbox, Goal Number, Goal Name, and up to 10 rows depending on amount of information in the table for that specific ID.

goals.php

<tr>
        <td valign=top colspan=3>
            Current Goals<br>
                <?php
                //this data is being pulled from 'main'
                    $result = mysql_query("SELECT * FROM main WHERE idnumber = $idnumber ORDER BY goalnumber");
                    if ($result) {
                    $total_rows = mysql_numrows($result);
                    } else { $total_rows = 0; }
                    print "<table border=1 width=400>\n";
                    print "<tr> \n";
                    print "<th> Checkbox </th> \n";
                    print "<th> Goal Number </th> \n";
                    print "<th> Goal Name </th> \n";
                    print "</tr> \n";
                    //}
                    $i = 0;
                    while ( $i < $total_rows )
                    {
                    $goalno = intval(mysql_result($result, $i, "goalnumber"));
                    $goalname = mysql_result($result, $i, "goalname");
                    $goal_id = intval(mysql_result($result, $i, "goal_id"));
                    print "<tr> \n";
                    print "<td> <center><input type=\"checkbox\" name=\"goal_id_$i\" value=\"$goalnumber - $goalname\"></td> \n";
                    print "<td> $goalnumber </td> \n";
                    print "<td> $goalname </td> \n";
                    print "</tr> \n";
                    $i = $i + 1;
                    }
                ?>
                </table>
        </td>

Once a user checks anywhere from 1-10 of these checkboxes and submits the form, I need to pass the values of said selections to the db (each selection should be written to a new field in the db table ‘updated_goals’. On submit the below file gets called. Note that I am writing the checkbox value to a different table in the same db ‘updated_goals’. I am not sure where I am going wrong with the code, but the goal is to write the values of the checkbox, “$goalnumber – $goalname” into the goal_id field.

goals_submit.php

// process data in table: updated_goals
$query = "SELECT idnumber from updated_goals where idnumber = {$_POST['idnumber']}";
$result = mysql_query($query);
$total_rows = mysql_numrows($result);

            //writing data to 'updated_goals'

        if (isset($_POST ['goal_id_$i'])) { $goal_id = ReplaceQuotes($_POST['goal_id_$i']); } else { $goal_id = ""; }

    $query = "INSERT INTO updated_goals ( ";
    $query .= "goal_id ";
    $query .= ") VALUES ( ";
    $query .= "'$goal_id' ";
    $query .= ")";
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1 Answer

  1. Editorial Team

    Possible solutions:

    Change this line:

    if (isset($_POST ['goal_id'][$i])) { $goal_id = ReplaceQuotes($_POST['goal_id'][$i]); } else { $goal_id = ""; }

    to 

    if (isset($_POST ['goal_id_'.$i])) { $goal_id = ReplaceQuotes($_POST['goal_id_'.$i]); } else { $goal_id = ""; }

    or
    change this line

    print "<td> <center><input type=\"checkbox\" name=\"goal_id_$i\" value=\"$goalnumber - $goalname\"></td> \n";

    to 

    print "<td> <center><input type=\"checkbox\" name=\"goal_id[$i]\" value=\"$goalnumber - $goalname\"></td> \n";

    if array used for input name for example:
    inputname[]
    it can be get via POST or GET by $_POST[‘inputname’][index] or $_GET[‘inputname’][index]

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