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Home/ Questions/Q 9061645
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T15:32:17+00:00 2026-06-16T15:32:17+00:00

Currently am creating files using the below code,I want to create a directory based

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Currently am creating files using the below code,I want to create a directory based on the timestamp at that point in the cwd,save the directory location to a variable and then create the file in the newly created directory,does anyone have ideas on how can this be done?

def filecreation(list, filename):
    #print "list"
    with open(filename, 'w') as d:
        d.writelines(list)

def main():
    list=['1','2']
    filecreation(list,"list.txt")

if __name__ == '__main__':
    main()
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  1. Editorial Team
    Editorial Team
    2026-06-16T15:32:19+00:00Added an answer on June 16, 2026 at 3:32 pm

    You mean, something like this?

    import os, datetime
    mydir = os.path.join(os.getcwd(), datetime.datetime.now().strftime('%Y-%m-%d_%H-%M-%S'))
    os.makedirs(mydir)
    with open(os.path.join(mydir, 'filename.txt'), 'w') as d:
        pass # ... etc ...
    

    Complete function

    import errno
    import os
    from datetime import datetime
    
    def filecreation(list, filename):
        mydir = os.path.join(
            os.getcwd(), 
            datetime.now().strftime('%Y-%m-%d_%H-%M-%S'))
        try:
            os.makedirs(mydir)
        except OSError as e:
            if e.errno != errno.EEXIST:
                raise  # This was not a "directory exist" error..
        with open(os.path.join(mydir, filename), 'w') as d:
            d.writelines(list)
    

    Update: check errno.EEXIST constant instead of hard-coding the error number

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