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Home/ Questions/Q 6681963
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:39:02+00:00 2026-05-26T04:39:02+00:00

Currently i am working on a project where i need to match people based

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Currently i am working on a project where i need to match people based on the categories of food they like:

This is the scenario:

I have a list of USERS and their favorite foods in my database. The database structure is as follows:

USERS(id,name,email,gender,dob)
Fav_Food (id,user_name,food,desc)

Data for users table:

1, Alice, alice@lala.com, female, 11 Oct 2010

2, Bob, bob@lala.com, male, 12 Oct 2010

3, Jason, jason@lala.com, male, 13 Oct 2010

Data for fav_foods table:

1, Alice, apple, some desc

2, Alice, banana, some desc

3, Alice, Pear, some desc

4, Bob, apple, some desc

5, Bob, custard cake, some desc

6, Jason, banana,some desc

6,Jason,apple,some desc

Imagine that i am Alice where i like apple,banana & pear. How would i be able to match people based on the favorite food? For example, i first check if anyone likes apple,banana and pear (inclusive of all three) and than go with the permutation of only two combination (apple,banana)(apple,pear)(banana,pear)(banana,apple) ….and so on…..

Imagine it like a Venn diagram where the interaction is what i am interested. I am interested to suggest users with the most matched. Is there any algorithm available that i can use for php?

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:39:03+00:00Added an answer on May 26, 2026 at 4:39 am

    what you could do is join the fav_foods table to itself and then count the matches:

    SELECT u2.user_name,count(*) as likeness 
    FROM `fav_food` as u1 INNER JOIN `fav_food` as u2 ON (u1.user_name = 'alice' AND 
                                                     u1.food = u2.food AND 
                                                     u2.user_name != "alice")
    GROUP BY u2.user_name 
    ORDER BY likeness DESC
    

    it will output:

    user_name   likeness
    jason       2
    bob         1
    

    the trick is on the conditions of the inner join… =)

    Hope this helps

    EDITED: oops i corrected the query =)

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