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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:05:57+00:00 2026-05-11T21:05:57+00:00

Currently, I have a String object that contains XML elements: String carsInGarage = garage.getCars();

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Currently, I have a String object that contains XML elements:

String carsInGarage = garage.getCars();

I now want to pass this String as an input/stream source (or some kind of source), but am unsure which one to choose and how to implement it.

Most of the solutions I have looked at import the package: javax.xml.transform and accept a XML file (stylerXML.xml) and output to a HTML file (outputFile.html) (See code below).

try 
{
    TransformerFactory tFactory = TransformerFactory.newInstance();
    Transformer transformer = tFactory.newTransformer(new StreamSource("styler.xsl"));

    transformer.transform(new StreamSource("stylerXML.xml"), new StreamResult(new FileOutputStream("outputFile.html")));
}
catch (Exception e)
{
    e.printStackTrace();
}

I want to accept a String object and output (using XSL) to a element within an existing JSP page. I just don’t know how to implement this, even having looked at the code above.

Can someone please advise/assist. I have searched high and low for a solution, but I just can’t pull anything out.

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:05:57+00:00Added an answer on May 11, 2026 at 9:05 pm

    Use a StringReader and a StringWriter:

    try {
        StringReader reader = new StringReader("<xml>blabla</xml>");
        StringWriter writer = new StringWriter();
        TransformerFactory tFactory = TransformerFactory.newInstance();
        Transformer transformer = tFactory.newTransformer(
                new javax.xml.transform.stream.StreamSource("styler.xsl"));
    
        transformer.transform(
                new javax.xml.transform.stream.StreamSource(reader), 
                new javax.xml.transform.stream.StreamResult(writer));
    
        String result = writer.toString();
    } catch (Exception e) {
        e.printStackTrace();
    }
    
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