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Home/ Questions/Q 350637
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T11:34:06+00:00 2026-05-12T11:34:06+00:00

Currently, I have some code as follows template<typename Type> Type* getValue(std::string name, bool tryUseGetter

  • 0

Currently, I have some code as follows

template<typename Type>
Type* getValue(std::string name, bool tryUseGetter = true)
{
    if(tryUseGetter)
    {
        if(_properties[name]->hasGetter)
        {
            return (Type*)_properties[name]->getter();
        }
        return (Type*)_properties[name]->data;
    }
    else
    {
        return (Type*)_properties[name]->data;
    }
}

Is there a way to make tryUseGetter a compile time switch? i.e. move it to the template declaration so it’s something akin to this

template<typename Type, bool tryUseGetter = true>
...

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T11:34:07+00:00Added an answer on May 12, 2026 at 11:34 am

    You could use type cast operator and structure getValue as follows (usage syntax will be the same as with function) :

    template<typename Type, bool tryUseGetter = true> 
    struct getValue {};
    
    template<typename Type>
    struct getValue<Type, true> {
        getValue(const std::string& name) : name(name) {};
        operator Type*() const {
            if(_properties[name]->hasGetter) {
                return (Type*)_properties[name]->getter();
            }
            return (Type*)_properties[name]->data;
        }
    private:
        const std::string& name;
    };
    
    template<typename Type>
    struct getValue<Type, false> {
        getValue(const std::string& name) : name(name) {};
        operator Type*() const {
            return (Type*)_properties[name]->data;
        }
    private:
        const std::string& name;
    };
    

    Usage:

    int main () {
        int* i = getValue<int>( "TEST" ); // true by default
        Xstruct* x = getValue<Xstruct, false>( "XS" ); // false
    }
    
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