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Home/ Questions/Q 7519901
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T01:58:40+00:00 2026-05-30T01:58:40+00:00

Currently I’m using: int a=10; if(a=20) printf(TRUE); else printf(false); Which prints, in C, the

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Currently I’m using:

 int a=10;
 if(a=20)
     printf("TRUE");
 else
     printf("false");

Which prints, in C, the value TRUE.

But in case of java:

int a=10;
if(a=20)
    System.out.println("TRUE");
else
    System.out.println("FALSE");

I’ll get a compile time error about an incompatible type.

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  1. Editorial Team
    Editorial Team
    2026-05-30T01:58:41+00:00Added an answer on May 30, 2026 at 1:58 am

    The reason for that is that in C there is no specific type boolean – instead any non-0 integer evaluates to a boolean “true”. Thus in your C code:

    if(a=20)
    

    a is assigned the value 20, which is non-0 – and the condition is evaluated as true

    In java, there’s a fundamental type boolean and the value of the conditional inside if must be of this type.

    a=20
    

    in Java assigns 20 to a and returns the final result of evaluation as integer value 20, however type boolean is expected – hence you’re getting a compile-time error about the incompatible types.

    If you want to do a comparison of a with 20, however, you need to use == operator both in C and Java:

    if(a == 20)
    

    This will compile in both C and Java and print FALSE in both languages.

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