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Home/ Questions/Q 3277740
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:24:10+00:00 2026-05-17T19:24:10+00:00

Currently this function works : it displays for a specific game, how many jobs

  • 0

Currently this function works : it displays for a specific game, how many jobs there are.

The problem : If there is no job, the game does not appear on the list.

How to display the game even if there is no job attached ?

Thanks

public function getWithGames()
    {
        $q = $this->createQuery('c')
            ->leftJoin('c.stJob j')
            ->where('j.expires_at > ?', date('Y-m-d h:i:s', time()))
            ->addOrderBy('c.name');

        $q->andWhere('j.is_activated = ?', 1);
        $q->andWhere('j.is_public = ?', 1);


        return $q->execute();
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T19:24:11+00:00Added an answer on May 17, 2026 at 7:24 pm

    Your conditions should be part of the LEFT JOIN … ON clause.

    $q = $this->createQuery('c')
        ->leftJoin('c.stJob j WITH j.expires_at > ? AND j.is_activated = 1 AND j.is_public = 1', date('Y-m-d h:i:s', time()))
        ->addOrderBy('c.name');
    

    Putting conditions in the ON clause (as opposed to the WHERE) indicates that they apply specifically to the JOIN. If no rows satisfy those conditions, there is no join — and that’s just what you want in this case. Putting them in the WHERE indicates that the result rows must satisfy those conditions. And obviously if there was no join, you can’t satisfy any conditions about the j table.

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