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Home/ Questions/Q 7960847
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T04:52:27+00:00 2026-06-04T04:52:27+00:00

Cursor cursor = db.rawQuery(SELECT id,lastname,status FROM people WHERE + id = + IncomingiD +

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 Cursor cursor = db.rawQuery("SELECT id,lastname,status FROM people WHERE " + "id = "+ IncomingiD +" FROM people WHERE status =100 ); ",null);

I want to access to “status=100 and id=incomingid” of my people table. I wrote above snipped code but I am getting an error below…. What is wrong with that query ? Could you please help me ?

E/Error(996): Error while openining peopleandroid.database.sqlite.SQLiteException: near "FROM": syntax error: , while compiling: SELECT id,lastname,status FROM people WHERE  id = 1 FROM places WHERE status =100 ); 
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  1. Editorial Team
    Editorial Team
    2026-06-04T04:52:30+00:00Added an answer on June 4, 2026 at 4:52 am

    You have the FROM people part twice in your query :

    • First, at the correct place, between the select and where clause
    • And then, a second time, after the first condition in the where clause.

    Also, note that you have where twice in your query — the two condition should be separated by and and, and not a second where.

    Oh, and it also seems that you have a closing ) at the end of your query?

    Basically, your query looks like this :

    SELECT id,lastname,status 
    FROM people 
    WHERE id = ....
    FROM people 
    WHERE status =100 
    ); 
    

    But it should be looking like that :

    SELECT id,lastname,status 
    FROM people 
    WHERE id = ....
        and status = 100 
    

    In the end, I’m guessing your Java code should look a bit like this :

    Cursor cursor = db.rawQuery("SELECT id, lastname, status FROM people WHERE id = " + IncomingiD + " AND status = 100",null);
    
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